How do you solve #sqrt(x+9)=6#?

1 Answer
Apr 10, 2017

Answer:

#x=27#

Explanation:

To 'undo' the root #color(blue)"square both sides"# of the equation.

#(sqrt(x+9))^2=6^2#

#rArrx+9=36#

subtract 9 from both sides.

#xcancel(+9)cancel(-9)=36-9#

#rArrx=27#

#color(blue)"As a check"#

Substitute this value into the left side and if equal to the right side then it is the solution.

#sqrt(27+9)=sqrt36=6=" right side"#

#rArrx=27 " is the solution"#