How do you solve #sqrt(x+9)=6#?
1 Answer
Apr 10, 2017
Explanation:
To 'undo' the root
#color(blue)"square both sides"# of the equation.
#(sqrt(x+9))^2=6^2#
#rArrx+9=36# subtract 9 from both sides.
#xcancel(+9)cancel(-9)=36-9#
#rArrx=27#
#color(blue)"As a check"# Substitute this value into the left side and if equal to the right side then it is the solution.
#sqrt(27+9)=sqrt36=6=" right side"#
#rArrx=27 " is the solution"#
