# How do you solve sqrt25 - 3x -6 = 1?

Jul 24, 2015

You isolate $x$ on one side of the equation.

#### Explanation:

The thing to notice about this equation is that $\sqrt{25}$ is actually equal to

sqrt(25) = sqrt(5""^2) = 5

This means that your original equation becomes

$5 - 3 x - 6 = 1$

You can easily solve this by first isolating $- 3 x$ on one side of the equation first. Start from

$- 1 - 3 x = 1$

Add $+ 1$ to both sides of the equation to get

$\cancel{- 1} + \cancel{1} - 3 x = 1 + 1$

$- 3 x = 2$

Now divide both sides of the equation by $- 3$ to get

$\frac{\cancel{- 3} \cdot x}{\cancel{- 3}} = \frac{2}{-} 3$

$x = \textcolor{g r e e n}{- \frac{2}{3}}$