How do you solve #sqrtj + sqrtj + 14 = 3sqrtj +10 #?

2 Answers
Feb 28, 2016

Answer:

#j=16#

Explanation:

Given:#" "sqrt(j) + sqrt(j)+14" "=" "3sqrt(j)+10#

Write as:#" " 2sqrt(j)+14" "=" "3sqrt(j)+10#

Collecting like terms

#" "3sqrt(j)-2sqrt(j)" " =" "14-10#

#sqrt(j)" "=" "4#

Squaring both sides

#j=4^2=16#

Feb 28, 2016

Answer:

j = 16

Explanation:

Collect terms in j to the left and numbers to the right.

hence #2sqrtj - 3sqrtj = 10 - 14 → -sqrtj = -4#

multiply both sides by (-1) to obtain : # sqrtj = 4 #

now square both sides.

#rArr (sqrtj)^2 = 4^2 rArr j = 16 #