How do you solve #sqrtn-3=6# and check your solution?

1 Answer
Jan 18, 2017

Answer:

See the entire solution and verification process below:

Explanation:

Step 1) Add #color(red)(3)# to each side of the equation to isolate the #n# term while keeping the equation balanced:

#sqrt(n) - 3 + color(red)(3) = 6 + color(red)(3)#

#sqrt(n) - 0 = 9#

#sqrt(n) = 9#

Step 2) Square each side of the equation to solve for #n# while keeping the equation balanced:

#(sqrt(n))^2 = 9^2#

#n = 81#

To check the solution we substitute #color(red)(81)# for #color(red)(n)#, evaluate the left side of the equation and ensure it equals the right side of the equation:

#sqrt(color(red)(n)) - 3 = 6# becomes:

#sqrt(color(red)(81)) - 3 = 6#

#9 - 3 = 6#

#6 = 6#