Question

How do you solve `sqrtx+3sqrtx=sqrt(17x-4)`?

Answer 1

`x= 4`

Explanation:

`sqrt(x) + 3sqrt(x) = sqrt (17x-4) or sqrt x (3+1) = sqrt (17x-4)` or

`4sqrt(x) = sqrt (17x-4)`, squaring both sides we get,

`16 x = 17x -4 or x = 4` [Ans]