How do you solve #sqrtx+9=4#?
As it stands, your equation has no possible solutions among real numbers.
To see why that is the case, isolate the radical term on one side of the equation by adding
#sqrt(x) + color(red)(cancel(color(black)(9))) - color(red)(cancel(color(black)(9))) = 4-9#
#sqrt(x) = -5#
For real numbers, you have
#color(blue)(sqrt(x)>=0, (AA)x >=0)#
Simply put, the square root of a positive real number, which is what must be to begin with, is always positive.
In your case, the square root of
Therefore, your equation has no solution for any