# How do you solve #sqrtx+9=4#?

##### 1 Answer

Aug 11, 2015

#### Answer:

#### Explanation:

As it stands, your equation has no possible solutions among *real numbers*.

To see why that is the case, isolate the radical term on one side of the equation by adding

#sqrt(x) + color(red)(cancel(color(black)(9))) - color(red)(cancel(color(black)(9))) = 4-9#

#sqrt(x) = -5#

For *real numbers*, you have

#color(blue)(sqrt(x)>=0, (AA)x >=0)#

Simply put, the square root of a positive real number, which is what must be to begin with, is **always** positive.

In your case, the square root of

Therefore, your equation has no solution for any