How do you solve #sqrtx (sqrt9 - 4÷3) = sqrt25#?

1 Answer
Sep 26, 2015

Answer:

Remember PEMDAS

Explanation:

  • Do inside (), and turn division to fraction. It will look like

#sqrt(x) * (3-4/3) = sqrt(25)#

  • To finish (), you need LCD. LCD will be #3#, and turn 3 to #(9/3)#.

What is #9/3 - 4/3#? It will look like after all of this

#sqrt(x) * (5/3) = sqrt(25)#

  • Take square root of #25#. It will look like

#sqrt(x) * (5/3)=5#

  • Multiply each side by #3/5#. It will look like

#sqrt(x) * cancel(5/3) * cancel(3/5) = cancel(5) * 3/cancel(5)#

#sqrt(x) = 3#

  • Now take the square of each side. It will look like

#(sqrt(x))^2 = 3^2#

#x = 9#

Here is a link to a video how to solve this problem: