How do you solve #sqrtx (sqrt9 - 4÷3) = sqrt25#?
1 Answer
Remember PEMDAS
Explanation:
- Do inside (), and turn division to fraction. It will look like
#sqrt(x) * (3-4/3) = sqrt(25)#
- To finish (), you need LCD. LCD will be
#3# , and turn 3 to#(9/3)# .
What is
#sqrt(x) * (5/3) = sqrt(25)#
- Take square root of
#25# . It will look like
#sqrt(x) * (5/3)=5#
- Multiply each side by
#3/5# . It will look like
#sqrt(x) * cancel(5/3) * cancel(3/5) = cancel(5) * 3/cancel(5)#
#sqrt(x) = 3#
- Now take the square of each side. It will look like
#(sqrt(x))^2 = 3^2#
#x = 9#
Here is a link to a video how to solve this problem:
