# How do you solve sqrtx (sqrt9 - 4÷3) = sqrt25?

Sep 26, 2015

Remember PEMDAS

#### Explanation:

• Do inside (), and turn division to fraction. It will look like

$\sqrt{x} \cdot \left(3 - \frac{4}{3}\right) = \sqrt{25}$

• To finish (), you need LCD. LCD will be $3$, and turn 3 to $\left(\frac{9}{3}\right)$.

What is $\frac{9}{3} - \frac{4}{3}$? It will look like after all of this

$\sqrt{x} \cdot \left(\frac{5}{3}\right) = \sqrt{25}$

• Take square root of $25$. It will look like

$\sqrt{x} \cdot \left(\frac{5}{3}\right) = 5$

• Multiply each side by $\frac{3}{5}$. It will look like

$\sqrt{x} \cdot \cancel{\frac{5}{3}} \cdot \cancel{\frac{3}{5}} = \cancel{5} \cdot \frac{3}{\cancel{5}}$

$\sqrt{x} = 3$

• Now take the square of each side. It will look like

${\left(\sqrt{x}\right)}^{2} = {3}^{2}$

$x = 9$

Here is a link to a video how to solve this problem: