How do you solve T+28+T=4(T-13)?

Jun 15, 2017

$T = 40$

Explanation:

$T + 28 + T = 4 \left(T - 13\right)$

$T + 28 + T = 4 T - 52$

$T + T = 4 T - 52 - 28$

$T + T - 4 T = - 52 - 28$

$- 2 T = - 52 - 28$

$- 2 T = - 80$

T = -80 ÷ -2

color(blue)(T = 40

Now we can put $40$ in for $T$ to prove our answer.

$40 + 28 + 40 = 4 \left(40 - 13\right)$

$68 + 40 = 4 \left(40 - 13\right)$

$68 + 40 = 4 \times 27$

$68 + 40 = 108$

$108 = 108$