Question

How do you solve `\tan x + \cot x = 2`?

Answer 1

`x = pi/4 + kpi`

Explanation:

`tan x + 1/(tan x) - 2 = 0`
`tan^2 x - 2tan x + 1 = 0`
`(tan x - 1)^2 = 0`
`tan x = 1`
Trig table and unit circle give:
`x = pi/4 + kpi, k in ZZ.`