Question

How do you solve `tan3x(tanx-1)=0`?

Answer 1

`x=(npi)/3` or `x=npi+pi/4`, where `n` is an integer.

Explanation:

As `tan3x(tanx-1)=0`

We have either `tan3x=0`, which gives us

`3x=npi`, where `n` is an integer i.e. `x=(npi)/3`

or `tanx-1=0` i.e. `tanx=tanpi/4` which gives us

`x=npi+pi/4`