How do you solve (tanx-1)(2sinx+1)=0?
1 Answer
May 15, 2016
degrees:
radians:
Explanation:
Given,
(tanx-1)(2sinx+1)=0
In order for the equation to equal to
tanx-1=0color(white)(XXXXXXX)2sinx+1=0
tanx=1color(white)(XXXXXXXXX)sinx=-1/2
x=color(green)(ul(color(black)(45^@))) orcolor(green)(ul(color(black)(225^@)))color(white)(XXXXXX)x=color(green)(ul(color(black)(210^@))) orcolor(green)(ul(color(black)(330^@)))
color(white)(XXx)color(green)(ul(color(black)(pi/4))) orcolor(green)(ul(color(black)(5/4pi)))color(white)(XXXXXXXXXx)color(green)(ul(color(black)(7/6pi))) orcolor(green)(ul(color(black)(11/6pi)))