# How do you solve tanxsinx-tanx=0 in the interval [0,360]?

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Nghi N Share
May 23, 2018

#### Answer:

$0 , \frac{\pi}{2} , \pi , 2 \pi$, or
0, 90, 180, 360

#### Explanation:

f(x) = tan x.sin x - tan x = 0
f(x) = tan x (sin x - 1) = 0
Either factor should be zero
a. tan x = 0
Unit circle --> x = 0, $x = \pi , x = 2 \pi$
b. sin x - 1 = 0 --> sin x = 1
$x = \frac{\pi}{2}$

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