Question

How do you solve the equation `log_7 24-log_7(y+5)=log_7 8`?

Answer 1

`y=-2`

Explanation:

`log_7 24-log_7 (y+5)=log_7 8`

`hArrlog_7(24/(y+5))=log_7 8`

hence `24/(y+5)=8`

or `24=8xx(y+5)`

or `y+5=24/8=3`

and `y=3-5=-2`