Question

How do you solve the following equation `Cosθ + 1 = 1` in the interval [0, 2pi]?

Answer 1

`theta=pi/2` or `theta=(3pi)/2`

Explanation:

As `costheta+1=1`, we have `costheta=1-1=0`

Now in the interval `[0,2pi]`,

`costheta` is `0` only at `theta=pi/2` and `theta=(3pi)/2`,

hence the solution.is `theta=pi/2` or `theta=(3pi)/2`