Question

How do you solve the following system of equations?: `13x+13y=16, 3x + 19y=19`?

Answer 1

`x=57/208` and `y=199/208`

Explanation:

`19*(13x+13y)-13*(3x+19y)=19*16-13*19`

`247x+247y-39x-247y=304-247`

`208x=57`, so `x=57/208`

Hence,

`3*57/208+19y=19`

`171/208+19y=19`

`19y=19-171/208`

`19y=3781/208`, so `y=199/208`