# How do you solve the following system of equations?: x-2y=13 , 3x-y=7?

$y = - \frac{32}{5}$
$x = x = \frac{1}{5}$
$x - 2 y = 13 \text{ "x=13+2y" } 3 x = 39 + 6 y$
$3 x - y = 7 \text{ "39+6y-y=7" } 32 = - 5 y$
$y = - \frac{32}{5}$
$x - 2 \left(- \frac{32}{5}\right) = 13 \text{ "x=13-64/5" } x = \frac{1}{5}$