Question

How do you solve the following system of equations?: `x-2y=13 , 3x-y=7`?

Answer 1

`y=-32/5`
`x=x=1/5`

Explanation:

`x-2y=13" "x=13+2y" "3x=39+6y`
`3x-y=7" "39+6y-y=7" "32=-5y`
`y=-32/5`
`x-2(-32/5)=13" "x=13-64/5" "x=1/5`