How do you solve the following system of equations?: #x+y= -2 , 4x+3y=8 #?
In the two equations, get
#y= -4/3 x +8/3#.
Then you set the two equations equal to each other:
#-x-2= -4/3 x +8/3#.
Then you solve for
Solve by substitution and elimination:
We can eliminate
Now add both of the equations:
Now substitute the value of
You can check the answer and it will be correct! :)