Question

How do you solve the following system?: `-x+6y= - 2 , 5x - 2y= 3`

Answer 1

Make the first equation `x=6y+2` and substitute into the second equation.

Explanation:

By adding x and 2 to both sides of the first equation, we get:
`x=6y+2`
Now we substitute this expression of x into the second equation to get:
`5(6y+2)-2y=3` which we can distribute the 5 on the left hand side to get:
`30y+10-2y=3` which we combine the y-terms on the left hand side and subtract 10 from both sides:
`28y=-7` by dividing both sides by 28, we get:
`y=-1/4`

By substituting this value of y into the `x=6y+2` equation, we get:
`x=6(-1/4)+2`
`x=-3/2+2`
`x=1/2`
Therefore, our answer is the coordinate point `(1/2, -1/4)`