How do you solve the inequality #1/2x<=6#?

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Answer 1 · 2017-10-13T12:15:38

#x <= 12#

#1/2 x <= 6 => x <= 6/(1/2) => x <= 6*2 => x <= 12#

Hope that helped :)

Answer 2 · 2017-10-13T12:38:51

#x<=12#

#1/2 x <= 6#
Let's start by multiply both sides by #color(red)(2)#
#color(red)(2)(1/2 x) <= color(red)(2)(6)#
#(cancel2/cancel2 x)<=12#
#x <=12#