How do you solve the inequality $10 (x + 2) > 2 (6 - 9 x)$ $10(x+2)>2(6-9x)$ ?

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Answer 1 · 2016-01-31T11:50:13

$x > - \frac{2}{7}$ $x > -2/7$

We must simply first the inequality, both the left and right side :)

$10 (x + 2) > 2 (6 - 9 x)$ $10(x + 2) > 2(6 - 9x)$

using Distributive Property of Real Numbers:

$10 x + 20 > 12 - 18 x$ $10x + 20 > 12 - 18x$

then we must combine the same terms/like terms
(Using the Golden Rule of Algebra) (Balancing the Equation) :)

$28 x > - 8$ $28x > -8$

then divide both sides by $28$ $28$

$x > - \frac{8}{28}$ $x > -8 / 28$

reduce to lowest terms,

$x > - \frac{2}{7}$ $x > -2/7$

How do you solve the inequality 10(x+2)>2(6−9x)10(x+2)>2(6-9x)?