# How do you solve the inequality 14.1-2/5h>= -3/10h?

Nov 30, 2015

#h<=141

#### Explanation:

$14.1 - \frac{2}{5} h \ge - \frac{3}{10} h$

$14.1 = 14 \frac{1}{10} = \frac{141}{10}$

Rewrite the expression.

$\frac{141}{10} - \frac{2}{5} h \ge - \frac{3}{10} h$

Simplify $\frac{2}{5} h$ to $\frac{2 h}{5}$ and $\frac{3}{10} h$ to $\frac{3 h}{10}$.

$\frac{141}{10} - \frac{2 h}{5} \ge - \frac{3 h}{10}$

Multiply both sides by the common denominator $10$.

$141 - \frac{\left(2 h\right) \left(10\right)}{5} \ge - 3 h$

$141 - \frac{20 h}{5} \ge - 3 h$

Simplify.

$141 - 4 h \ge - 3 h$

Subtract $141$ from both sides.

$- 4 h \ge - 3 h - 141$

Add $3 h$ to both sides.

$3 h - 4 h \ge - 141$

Simplify.

$- h \ge - 141$

Multiply times $- 1$. This will remove the negative signs on both sides and reverse the inequality.

$h \le 141$