# How do you solve the inequality: #16x^2 + 24x < -9#?

##### 1 Answer

Aug 29, 2015

#### Answer:

#### Explanation:

First, move

#16x^2 + 24x + 9 <0#

Now, notice what happens when use

#16(x^2 + 24/16x + 9/16) <0#

You can write this as

#16 * [x^2 + 2 * (3/4)x + (3/4)^2] < 0#

#16 * (x + 3/4)^2 < 0#

The left-side of the inequality will **always** be positive, since

For **zero**, the smallest possible value it can take.

This means that your original inequality will not be satisfied, regardless of the value of