How do you solve the inequality $3 - 2 x > 7$ $3 - 2x > 7$ ?

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Answer 1 · 2018-05-29T09:56:21

$x < - 2$ $x<-2$

$3 - 2 x > 7$ $3-2x>7$

Subtract 3 from both sides
$- 2 x > 4$ $-2x>4$

Divide by 2
$- x > 2$ $-x>2$

Multiply by -1
$x < - 2$ $x<-2$

Answer 2 · 2018-05-29T09:57:31

Transpose terms

$3 - 7 > 2 x$ $3-7>2x$

$- 4 > 2 x$ $-4>2x$

Divide by 2 both sides

$- 2 > x$ $-2>x$ or if you want $x < - 2$ $x< -2$

The solution are all number smaller than -2

In interval form $(- \infty, - 2)$ $(-oo,-2)$ (excluded -2 because simbol is "<" estrictly)

How do you solve the inequality 3−2x>73 - 2x > 7?