How do you solve the inequality #3/4+3d < 6 3/4#?

1 Answer
Sep 18, 2015

Answer:

#d < 2#

Explanation:

So from #3/4 +3d < 6 + 3/4# we start by taking the LDC

#(3+4*3d)/4<(6*4+3)/4#

Then, we multiply both sides by 4
#4*(3+4*3d)/4<4*(6*4+3)/4 rarr 3+4*3d < 6*4+3#

The 3s cancel each other out
#3 +4*3d < 6*4 + 3 rarr 4*3d < 6*4#

We divide both sides by 4
#(4*3d)/4 < (6*4)/4 rarr 3d < 6#

Finally, divide both sides by 3
#(3d)/3 < 6/3 rarr d < 2#