# How do you solve the inequality 3-4(x-2) >=-5x+6?

Jul 21, 2018

$x \ge - 5$

#### Explanation:

$3 - 4 \left(x - 2\right) \ge - 5 x + 6$

Simplify the left hand side:
$3 - 4 x + 8 \ge - 5 x + 6$

$11 - 4 x \ge - 5 x + 6$

Add $\textcolor{b l u e}{5 x}$ to both sides:
$11 - 4 x \quad \textcolor{b l u e}{+ \quad 5 x} \ge - 5 x + 6 \quad \textcolor{b l u e}{+ \quad 5 x}$

$11 + x \ge 6$

Subtract $\textcolor{b l u e}{11}$ from both sides:
$11 + x \quad \textcolor{b l u e}{- \quad 11} > 6 \quad \textcolor{b l u e}{- \quad 11}$

$x \ge - 5$

Hope this helps!