How do you solve the inequality #3<5x-4<7#?
1 Answer
Mar 24, 2018
Explanation:
#"add 4 to each of the 3 intervals"#
#3color(red)(+4)< 5xcancel(-4)cancel(color(red)(+4))<7color(red)(+4)#
#rArr7 < 5x <11#
#"divide each interval by 5"#
#rArr7/5< x < 11/5#
#x in(7/5,11/5)larrcolor(blue)"in interval notation"#
