# How do you solve the inequality 4 - 4x > 5(3 + x) ?

Sep 14, 2015

$x < - \frac{11}{9}$

#### Explanation:

$4 - 4 x > 5 \left(3 + x\right)$

Expand the right side of the inequality.

$4 - 4 x > 15 + 5 x$

Subtract $4$ from both sides.

$- 4 x > 15 + 5 x - 4 =$

$- 4 x > 11 + 5 x$

Subtract $5 x$ from both sides.

$- 5 x - 4 x > 11 =$

$- 9 x > 11$

Divide both sides by $- 9$. (This will reverse the inequality.)

$x < \frac{11}{- 9} =$

$x < - \frac{11}{9}$