How do you solve the inequality #(4x-3)/2 - (3x-3)/3<3#?

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Answer 1 · 2016-07-14T17:20:12

#:. x<7/2#

Given that, #(4x-3)/2-(3x-3)/3<3.#

#:. (4x-3)/2-(3(x-1))/3<3#

#:. (4x-3)/2-(x-1)<3#

Multiplying by #2>0#, the order of the given inequality will not be reversed.

#:.4x-3-2(x-1)<6#

#:. 4x-3-2x+2<6#

#:. 2x-1<6.#

Adding #1#,

#2x-1+1=6+1#

#:. 2x<7#

Multiplying by #1/2>0#

#:. x<7/2#