How do you solve the inequality #5x<10(3x+4)#?
1 Answer
Apr 7, 2018
Explanation:
#"distribute the parenthesis on the right side"#
#rArr5x <30x+40#
#"subtract 5x from both sides"#
#cancel(5x)cancel(-5x)<30x-5x+40#
#rArr0< 25x+40#
#"subtract 40 from both sides"#
#0-40<25xcancel(+40)cancel(-40)#
#rArr-40<25x#
#"divide both sides by 25"#
#-40/25< x#
#rArr-8/5< x" or "x> -8/5#
