How do you solve the inequality #5x<10(3x+4)#?

1 Answer
Apr 7, 2018

Answer:

#x> -8/5#

Explanation:

#"distribute the parenthesis on the right side"#

#rArr5x <30x+40#

#"subtract 5x from both sides"#

#cancel(5x)cancel(-5x)<30x-5x+40#

#rArr0< 25x+40#

#"subtract 40 from both sides"#

#0-40<25xcancel(+40)cancel(-40)#

#rArr-40<25x#

#"divide both sides by 25"#

#-40/25< x#

#rArr-8/5< x" or "x> -8/5#