How do you solve the inequality $- 6 + 2 k < 6$ $-6+2k<6$ ?

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Answer 1 · 2015-09-27T20:48:04

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It is

$- 6 + 2 k < 6 \Rightarrow 2 k < 6 + 6 \Rightarrow 2 k < 12 \Rightarrow k < 6$ $-6+2k<6=>2k<6+6=>2k<12=>k<6$

Answer 2 · 2015-09-27T20:48:09

The answer is $k < 6$ $k<6$ .

$- 6 + 2 k < 6$ $-6+2k<6$

Add $6$ $6$ to both sides.

$2 k < 6 + 6 =$ $2k<6+6=$

$2 k < 12$ $2k<12$

Divide both sides by $2$ $2$ .

$k < \frac{12}{2} =$ $k<12/2=$

$k < 6$ $k<6$

How do you solve the inequality -6+2k<6−6+2k<6-6+2k<6?