How do you solve the inequality #-6 < x + 3 <6# ? Algebra Linear Inequalities and Absolute Value Compound Inequalities 1 Answer Rachel Jun 3, 2016 #-9<##x<3# Explanation: If we start with #-6<##x+3<6#, we can begin by breaking this one expression into to, like so: #-6<##x+3# and #x+3<6#. Now we can solve for the two different #x#s. #-6<##x+3#, minus #3# on both sides, and we have #-9<##x#. With #x+3<##6#, we once again subtract #3# on both sides, which leaves us with #x<3#. So, #x# can be greater than #-9# and smaller that #3#, which we can write as #-9<##x<3# Answer link Related questions How do you solve compound inequalities? What is an example of an inequality that uses "and" and what inequality uses "or"? How do you graph #-40 \le y < 60# on a number line? How do you solve for x in #3x-5 < x + 9 \le 5x + 13 #? How do you solve #9-2x \le 3 or 3x+10 \le 6-x#? How do you solve for b given #6+b<8 or b+6 \ge 6#? How do you graph #x ≥ 4# or #x > -4#? How do you solve the compound inequality #-20≤-6m-2≤58# and graph its solution? How do you graph #-53<9v+1<-26#? How do you graph this inequality: #15<x<30#? See all questions in Compound Inequalities Impact of this question 1776 views around the world You can reuse this answer Creative Commons License