How do you solve the inequality $-8 < 2(x+3)$ and $2(x+3) <8$ ?

Question

1914 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-16T12:54:59

$-7<x<1$

$-8<2x+6<8$ combine them and distribute
$-14<2x<2$ subtract 6
$-7<x<1$ divide by 2

How do you solve the inequality -8 < 2(x+3)-8 < 2(x+3) and 2(x+3) <82(x+3) <8?