# How do you solve the inequality 8x - 9 < 3x - 11?

Mar 28, 2018

See below

#### Explanation:

$8 x - 9 < 3 x - 11$. Transposing terms

$8 x - 3 x < - 11 + 9$

$5 x < - 2$

$x < - \frac{2}{5}$

The solution are all those numbers smaller than $- \frac{2}{5}$. In interval form, the solution are $x$ such that

$x \in \left(- \infty , - \frac{2}{5}\right)$