How do you solve the inequality $-9 - e > 3e + 11$ ?

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Answer 1 · 2018-07-24T19:03:37

$e < -5$

$-9 - e > 3e + 11$

Add $color(blue)e$ to both sides:
$-9 - e quadcolor(blue)(+quade) > 3e + 11 quadcolor(blue)(+quade)$

$-9 > 4e + 11$

Subtract $color(blue)11$ from both sides:
$-9 quadcolor(blue)(-quad11) > 4e + 11 quadcolor(blue)(-quad11)$

$-20 > 4e$

Divide both sides by $color(blue)4$ :
$(-20)/color(blue)4 > (4e)/color(blue)4$

$-5 > e$

Therefore,
$e < -5$

Here's a graph of it on a number line:
enter image source here

The open circle on $-5$ means that $-5$ is not a solution (but anything else less than it).

Hope this helps!

How do you solve the inequality -9 - e > 3e + 11-9 - e > 3e + 11?