How do you solve the inequality #-9 - e > 3e + 11#?

1 Answer
Jul 24, 2018

Answer:

#e < -5#

Explanation:

#-9 - e > 3e + 11#

Add #color(blue)e# to both sides:
#-9 - e quadcolor(blue)(+quade) > 3e + 11 quadcolor(blue)(+quade)#

#-9 > 4e + 11#

Subtract #color(blue)11# from both sides:
#-9 quadcolor(blue)(-quad11) > 4e + 11 quadcolor(blue)(-quad11)#

#-20 > 4e#

Divide both sides by #color(blue)4#:
#(-20)/color(blue)4 > (4e)/color(blue)4#

#-5 > e#

Therefore,
#e < -5#

Here's a graph of it on a number line:
enter image source here

(mathwarehouse.com)

The open circle on #-5# means that #-5# is not a solution (but anything else less than it).

Hope this helps!