# How do you solve the inequality c/3 + 7 > 5 1/2?

Feb 28, 2016

$c > - \frac{9}{2}$

#### Explanation:

First, write $5 \frac{1}{2}$ as an improper fraction. Then, we can try to solve this like a typical equation.

$\frac{c}{3} + 7 > 5 + \frac{1}{2}$

$\frac{c}{3} + 7 > \frac{10}{2} + \frac{1}{2}$

$\frac{c}{3} + 7 > \frac{11}{2}$

Subtract $7$ from both sides.

$\frac{c}{3} > \frac{11}{2} - 7$

$\frac{c}{3} > \frac{11}{2} - \frac{14}{2}$

$\frac{c}{3} > - \frac{3}{2}$

Multiply both sides of the inequality by $3$.

$c > - \frac{9}{2}$