# How do you solve the inequality d + 6 ≤ 4d - 9 or 3d -1 <2d + 4?

Aug 12, 2018

$d + 6 \le q 4 d - 9$

Subtract $d$ from both sides

$6 \le q 3 d - 9$

$15 \le q 3 d$

Divide by 3

$5 \le q d$

$3 d - 1 < 2 d + 4$

Subtract $2 d$ from both sides

$d - 1 < 4$

$d < 5$