How do you solve the inequality #(x +4) + (x+6)> 3x - 1#?

1 Answer
Feb 4, 2016

Answer:

#x<11#

Explanation:

1. Add like terms.

#(x+4)+(x+6)>3x-1#

#2x+10>3x-1#

2. Subtract 10 from both sides.

#2x+10# #color(red)(-10)>3x-1# #color(red)(-10)#

#2x>3x-11#

3. Subtract 3x from both sides.

#2x# #color(red)(-3x)>3x# #color(red)(-3x)-11#

#-x##>##-11#

4. Divide both sides by -1.

#-xcolor(red)(-:-1)##>##-11color(red)(-:-1)#

#x>11#

5. Flip the inequality sign.
Whenever you divide by a negative number, you must flip the inequality sign, even if you divide a negative number by another negative number.

#color(green)(x<11)#