# How do you solve the quadratic using the quadratic formula given #2a^2-6a-3=0# over the set of complex numbers?

##### 1 Answer

May 13, 2017

The solution does not require complex numbers.

#### Explanation:

You simply put the coefficients of the equation into the formula and solve it algebraically.

For

In this case, a = 2, b = -6 and c = -3

**CHECK** : 2*(-0.4375^2) – 6*(-0.4375) -3 = 0 ; 2*(0.19) + 2.62 – 3 = 0 ;

0.38 + 2.62 – 3 = 0 ; 0 = 0 correct.

See http://www.purplemath.com/modules/quadform.htm for instructions.