How do you solve the quadratic using the quadratic formula given 2v^2-5v+3=0?

May 22, 2018

v=1.5 or 1

Explanation:

$v = \frac{- \left(- 5\right) \setminus \pm \sqrt{{\left(- 5\right)}^{2} - 4 \times 2 \times 3}}{2 \times 2}$

$v = \frac{5 \setminus \pm \sqrt{25 - 24}}{4}$

$v = \frac{5 + 1}{4} \mathmr{and} \frac{5 - 1}{4}$

$v = \frac{6}{4} \mathmr{and} \frac{4}{4}$

$v = \frac{3}{2} \mathmr{and} 1$