# How do you solve the quadratic using the quadratic formula given #3a^2-4a-4=0# over the set of complex numbers?

##### 1 Answer

Aug 15, 2016

This equation has 2 real roots:

#### Explanation:

To solve this equation using the quadratic formula first we calculate the determinant:

#Delta=b^2-4ac #

Now we can write the answer:

**The equation has 2 solutions #a_1=-2/3# and #a_2=2#.**