Question

How do you solve the quadratic using the quadratic formula given `8n^2-4n=18`?

Answer 1

`n=1.77`
`n=-1.27`

Explanation:

Given -

`8n^2-4n=18`

Rewrite the equation as

`8n^2-4n-18=0`

The formula is -

`n=(-b+-sqrt(b^2-(4ac)))/(2a)`

`n=((-(-4))sqrt((-4)^2-(4xx8xx(-18))))/(2xx8)`

`n=(4+-sqrt(16-(-576)))/16`
`n=(4+-sqrt(592))/16`
`n=(4+-24.33)/16`
`n=(4+24.33)/16=28.33/16=1.77`
`n=(4-24.33)/16=-20.33/16=-1.27`