How do you solve the quadratic using the quadratic formula given -c^2-6c+8=0 over the set of complex numbers?

1 Answer
Jan 2, 2018

c=(-6+-2sqrt(17))/2

Explanation:

The quadratic formula states that if you have an equation in the form:
nx^2+px+q=0

The solution(s) will be:
x=(-p+-sqrt(p^2-4nq))/(2n)

In our case n=-1,p=-6 and q=8, and applying the quadratic formula gives us:
c=(-(-6)+-sqrt((-6)^2-4*-1*8))/(2*-1)

c=(6+-sqrt(36-(-32)))/-2

c=-(6+-sqrt(36+32))/2

c=(-6+-sqrt(68))/2

c=(-6+-sqrt(2*2*17))/2

c=(-6+-2sqrt(17))/2