How do you solve the quadratic using the quadratic formula given k^2+5k-6=0?

Sep 29, 2016

$k = 1$
$k = - 6$

Explanation:

Given -

${k}^{2} + 5 k - 6 = 0$
$k = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
$k = \frac{- 5 \pm \sqrt{{5}^{2} - \left(4 \cdot 1 \cdot - 6\right)}}{2 \cdot 1}$
$k = \frac{- 5 \pm \sqrt{25 + 24}}{2 \cdot 1}$
$k = \frac{- 5 \pm \sqrt{49}}{2}$
$k = \frac{- 5 \pm 7}{2}$
$k = \frac{- 5 + 7}{2} = \frac{2}{2} = 1$
$k = \frac{- 5 - 7}{2} = \frac{- 12}{2} = - 6$