# How do you solve the quadratic using the quadratic formula given v^2+2v-8=0?

Jul 9, 2017

v = -4 or 2

#### Explanation:

$v = \frac{- b \setminus \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

where

$a = 1 , b = 2 , \mathmr{and} c = - 8$

Gives:

$v = \frac{- 2 \setminus \pm \sqrt{{2}^{2} - 4 \cdot 1 \cdot \left(- 8\right)}}{2 \cdot 1}$

$v = \frac{- 2 \setminus \pm \sqrt{4 + 32}}{2}$

$v = \frac{- 2 \setminus \pm \sqrt{36}}{2}$

$v = \frac{- 2 \setminus \pm 6}{2}$

$v = - \frac{8}{2} \mathmr{and} \frac{4}{2}$

$v = - 4 \mathmr{and} 2$