# How do you solve the quadratic using the quadratic formula given x^2+6x+13=0?

$- 3 \pm 2 i$
${x}^{2} + 6 x + 13 = 0$
$\Delta = {6}^{2} - 4 \cdot 1 \cdot 13 = 36 - 52 = - 16$
$\Delta < 0$
The solutions are in $\mathbb{C}$ not in $\mathbb{R}$
$x = \frac{- 6 \pm 4 i}{2} = - 3 \pm 2 i$