How do you solve the quadratic with complex numbers given #-5x^2+12x-8=0#?

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Answer 1 · 2018-01-30T01:26:56

#x = 1.2 - 0.1 sqrt26 color(red)i, 1.2 + 0.1 sqrt26 color(red)i#

#-5x^2 + 12x - 8 = 0#

#x = (-b +- sqrt(b^2 - (4 a c))) / (2 * a)#

#a = -5, b = 12, c = -8#

#x = (-12 +- sqrt(12^2 - (4 * -5 * - 8))) / (2 * -5)#

#x = (-12 +- sqrt(144 - 160)) / (-10)#

#x = 1.2+- 0.1 sqrt(-26)#

#x = 1.2 +- 0.1 sqrt26 color(red)i#