How do you solve the quadratic with complex numbers given #5x^2+8x=-4#?

1 Answer
Nov 24, 2016

Answer:

Use the quadratic formula! :)

"A negative boy couldn't decide on whether to go to a radical party. Since the boy was a square, he lost out on four awesome chicks. When the night was over, it was 2 a. m."

Explanation:

Negative Boy #=>-b#
Decide #=>+-#
Radical #=>sqrt#
Boy ... sqaure #=>b^2#
Lost #=>-#
Four Awesome Chicks #=>4ac#
Over ... 2 a.m. #=> 1/(2a)#

Fun little mnemonic for:

#(-b+-sqrt(b^2-4ac))/(2a)#