# How do you solve the quadratic with complex numbers given 5x^2+8x=-4?

Nov 24, 2016

Use the quadratic formula! :)

"A negative boy couldn't decide on whether to go to a radical party. Since the boy was a square, he lost out on four awesome chicks. When the night was over, it was 2 a. m."

#### Explanation:

Negative Boy $\implies - b$
Decide $\implies \pm$
Radical =>sqrt
Boy ... sqaure $\implies {b}^{2}$
Lost $\implies -$
Four Awesome Chicks $\implies 4 a c$
Over ... 2 a.m. $\implies \frac{1}{2 a}$

Fun little mnemonic for:

$\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$