How do you solve the quadratic with complex numbers given 8x^2-4x+5=0?

$x = \frac{1 \pm i 3}{4}$
$x = \frac{+ 2 \pm \sqrt[2]{4 - 5 \cdot 8}}{8} = \frac{+ 2 \pm \sqrt[2]{- 36}}{8} = \frac{2 \pm i 6}{8} = \frac{1 \pm i 3}{4}$