How do you solve the rational equation #2/ (5x-1) - 2/(3x+5) = 0#?

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Answer 1 · 2016-02-20T04:06:12

Put on an equal denominator

The Least Common Denominator would be #(5x - 1)(3x + 5)#

#(2(3x + 5))/((5x - 1)(3x + 5)) - (2(5x - 1))/((3x + 5)(5x - 1)) = 0#

Eliminating the denominators

6x + 10 - (10x - 2) = 0

-4x = -8

x = 2

Hopefully this helps!