# How do you solve the system 3x − 6y = 3 and 7x − 5y = −11 ?

May 20, 2015

Try this:

May 20, 2015

(1) 3x - 6y = 3 ---> Multiply by 5 -> 15x - 30y = 15 (1)

(2) 7x - 5y = -11 -> Multiply by -6 -> 42x + 30y = -66 (2)

Add (1) and (2) -> 57x = -51 ->$x = - \frac{51}{57} = - \frac{17}{19}$

6y = 3x - 3 = 3(x - 1) = 3(-36/19) = -108/19 ->$y = - \frac{108}{114.}$